(Solved) Present average age of A, B and C is 22 years. Three years ago, Average age of B and C is 18 years, then find A’s age 9 years hence? (a) 24 years (b) 27 years (c) 30 years (d) 33 years (e) 36 years

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 Question :

Present average age of A, B and C is 22 years. Three years ago, Average age of B and C is 18 years, then find A’s age 9 years hence? 

(a) 24 years

(b) 27 years

(c) 30 years

(d) 33 years

(e) 36 years


Solution :

Sum of present ages = A+B+C  = 22

                                               3

                                        A+B+C = 66


3 years ago sum of age of B and C

(B+C) + (C-3) = 18

           2

B+C- 6 = 18

     2

B+C-6 = 36

B+C = 42


Present age of A

A+B+C = 66

A+42 = 66

A = 66-42

A = 24


A's age 9 years hence

= 24 + 9

= 33 years


If any queries about Solution please comment below.



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