Terms and conditions

These terms and conditions ("Agreement") sets forth the general terms and conditions of your use of the educrucial.blogspot.com website ("Website" or "Service") and any of its related products and services (collectively, "Services"). This Agreement is legally binding between you ("User", "you" or "your") and this Website operator ("Operator", "we", "us" or "our"). By accessing and using the Website and Services, you acknowledge that you have read, understood, and agree to be bound by the terms of this Agreement. If you are entering into this Agreement on behalf of a business or other legal entity, you represent that you have the authority to bind such entity to this Agreement, in which case the terms "User", "you" or "your" shall refer to such entity. If you do not have such authority, or if you do not agree with the terms of this Agreement, you must not accept this Agreement and may not access and use the Website and Services. You acknowledge that this Agreement is a contract between you and the Operator, even though it is electronic and is not physically signed by you, and it governs your use of the Website and Services.

User content

We do not own any data, information or material (collectively, "Content") that you submit on the Website in the course of using the Service. You shall have sole responsibility for the accuracy, quality, integrity, legality, reliability, appropriateness, and intellectual property ownership or right to use of all submitted Content. We may monitor and review the Content on the Website submitted or created using our Services by you. You grant us permission to access, copy, distribute, store, transmit, reformat, display and perform the Content of your user account solely as required for the purpose of providing the Services to you. Without limiting any of those representations or warranties, we have the right, though not the obligation, to, in our own sole discretion, refuse or remove any Content that, in our reasonable opinion, violates any of our policies or is in any way harmful or objectionable. Unless specifically permitted by you, your use of the Website and Services does not grant us the license to use, reproduce, adapt, modify, publish or distribute the Content created by you or stored in your user account for commercial, marketing or any similar purpose.

Backups

We are not responsible for the Content residing on the Website. In no event shall we be held liable for any loss of any Content. It is your sole responsibility to maintain appropriate backup of your Content. Notwithstanding the foregoing, on some occasions and in certain circumstances, with absolutely no obligation, we may be able to restore some or all of your data that has been deleted as of a certain date and time when we may have backed up data for our own purposes. We make no guarantee that the data you need will be available.

Links to other resources

Although the Website and Services may link to other resources (such as websites, mobile applications, etc.), we are not, directly or indirectly, implying any approval, association, sponsorship, endorsement, or affiliation with any linked resource, unless specifically stated herein. We are not responsible for examining or evaluating, and we do not warrant the offerings of, any businesses or individuals or the content of their resources. We do not assume any responsibility or liability for the actions, products, services, and content of any other third parties. You should carefully review the legal statements and other conditions of use of any resource which you access through a link on the Website and Services. Your linking to any other off-site resources is at your own risk.

Changes and amendments

We reserve the right to modify this Agreement or its terms relating to the Website and Services at any time, effective upon posting of an updated version of this Agreement on the Website. When we do, we will revise the updated date at the bottom of this page. Continued use of the Website and Services after any such changes shall constitute your consent to such changes. Policy was created with WebsitePolicies.

Acceptance of these terms

You acknowledge that you have read this Agreement and agree to all its terms and conditions. By accessing and using the Website and Services you agree to be bound by this Agreement. If you do not agree to abide by the terms of this Agreement, you are not authorized to access or use the Website and Services.

Contacting us

If you would like to contact us to understand more about this Agreement or wish to contact us concerning any matter relating to it, you may do so via the contact form

This document was last updated on October 13, 2020

Popular posts from this blog

(Solved) A step down DC chopper has a resistive load of R = 15 ohm and input Vdc = 200 V. When the chopper remain ON, it's voltage drop is 2.5V. The chopper frequency is 1 kHz. If the duty cycle is 50%, determine: a) Average output voltage b) RMS output voltage c) Chopper efficiency d) The effective input resistance of the chopper

Image
Question:   A step down DC chopper has a resistive load of R = 15 ohm and input Vdc = 200 V. When the chopper remain ON, it's voltage drop is 2.5V. The chopper frequency is 1 kHz. If the duty cycle is 50%, determine:  a) Average output voltage  b) RMS output voltage  c) Chopper efficiency  d) The effective input resistance of the chopper Answer: We can get answers directly by applying relevant formulas as shown below.  (a) Average output voltage = 98.75 V (b) RMS output voltage = 139.6536 V (c) Chopper efficiency = 98.75% (d) The effective input resistance = 30.3799 ohm Additional information : Waveforms for step down chopper are shown below : For any queries regarding above solution please comment below. Thank you! 
Read more

(Solved) When a reverse bias is applied to a germanium PN junction diode, the reverse saturation current at room temperature is 0.3m A. Determine the current flowing in the diode when 0.15v forward bias is applied at room temperature.

  Question : When a reverse bias is applied to a germanium PN junction diode, the reverse saturation current at room temperature is 0.3m A. Determine the current flowing in the diode when 0.15v forward bias is applied at room temperature. Solution : Given Io = 0.3 * 10-6A and VF = 0.15v The current flowing through the PN diode under forward bias is I = Io (e^(40VF) -1) for germanium diode = 0.3 * 10^(-6) (e^(40*0.15) -1) = 120.73mA. For any further queries please comment below.  
Read more

(Solved) An LVDT is connected to an amplifier of gain 250 the output terminals of which are connected to a 5 V voltmeter. The meter's scale can be read to 1/5th of a division and has 100 divisions in all. Given that a core displacement of 0.5 mm provides an output of 2 mV from the LVDT, find, 1. The sensitivity of the LVDT 2. The sensitivity of the whole system 3. The resolution of the instrument in centimeters

Image
 Question : An LVDT is connected to an amplifier of gain 250 the output terminals of which are connected to a 5 V voltmeter. The meter's scale can be read to 1/5th of a division and has 100 divisions in all. Given that a core displacement of 0.5 mm provides an output of 2 mV from the LVDT, find,  1. The sensitivity of the LVDT  2. The sensitivity of the whole system  3. The resolution of the instrument in centimeters Explanation : (a) Sensitivity of LVDT = Output voltage /displacement  Sensitivity of LVDT = 2mV/0.5 mm = 4 mV/mm (b)Sensitivity of whole setup = amplification factor*sensitivity of LVDT  Sensitivity of whole setup = 250*(4 mV/mm) = 1000 mV/mm (c) The resolution of the instrument in centimeters = minimum voltage that can be read by instrument /sensitivity of whole setup  There are 100 divisions to measure upto 5V.  So 1 division can read 5/100 = 0.05V Scale can read 1/5 of a division.  So minimum voltage that can be read = 0.05/5 = 0.01V = 10mV So resolution = (10 mV) /
Read more