EDUCRUCIAL

  Question : Present average age of A, B and C is 22 years. Three years ago, Average age of B and C is 18 years, then find A’s age 9 years hence?  (a) 24 years (b) 27 years (c) 30 years (d) 33 years (e) 36 years Solution : Sum of present ages = A+B+C   = 22                                                3                                         A+B+C = 66 3 years ago sum of age of B and C (B+C) + (C-3)  = 18            2 B+C- 6 = 18      2 B+C-6 = 36 B+C = 42 Present age of A A+B+C = 66 A+42 = 66 A = 66-42 A = 24 A's age 9 years hence = 24 + 9 = 33 years If any queries about Solution please comment below.

  Question : A alone can do a work in 12 days while A and B together can do that work in 7.5 days. Find the time taken by C alone to do that work if C takes 3 days more than that of B alone to do that work? (a) 33 days (b) 30 days (c) 23 days (d) 27 days (e) 28 days Solution : Let B alone take x days to do the work A and B together in 1 days do 1/x = 1/7.5 - 1/12 1/x = 10/75 - 1/12 1/x = 2/15 - 1/12 1/x = 24 - 15/180 1/x = 9/180 1/x = 1/20 X = 20 days B alone done work = 20 days Here, c takes 3 days more than B 20+3 23 days C alone = 23 days  Here answer is option c =23 days.  For further queries please comment below. 

  Question: A and B working alone can do a work in 20 days and 15 days respectively. They started the work together but B left after sometime and A finished remaining work in 6 days. Find after how many days from start B left the work ? Solution: Efficiency Total work  3 - A - 20                          =     60 4 - B - 15 Here, 3+4=7 and A+B=60 Working done by A in last 6 days =6×3=18 Remaining done by A+B=60 Here, A=18 days A+B=60 18+B=60 B=60-18 B=42 days B left the work after = 42/7 = 6 days

  Question : The permissible voltage drop from supply terminal to any point on the wiring system should not exceed A. 4 % + 1 volt B. 3 % + 1 volt C. 2 % + 1 volt D. 1 % + 1 volt Answer : C. 2% + 1 Volt As per Indian Electricity rule, voltage drop (in lightening circuit of) wiring system should not exceed 2% + 1 volt. Note : Insulation resistance should be at least 1 Megaohm between two phases or phase and earth.  Insulation of line should be designed in such a way that leakage current from line to earth should not be more than 1/5000 part or 0.02%. 

  Question : The standard resistor is a coil of wire of some alloy having the properties of  Which of the above statements are correct? (a) Low electrical resistivity and high temperature coefficient of resistance (b) High electrical resistivity and high temperature coefficient of resistance. (c) Low electrical resistivity and low temperature coefficient of resistance. (d) High electrical resistivity and low temperature coefficient of resistance. Answer : (d) High electrical resistivity and low temperature coefficient of resistance. Explanation : Standard resistors are made of very complex alloys.  These alloys have high electrical resistivity and low temperature coefficient of resistance. So change in resistance of standard resistor with change in temperature should be less.  Manganin is mainly used to make standard resistance.  Manganin = (80-85)% cu + (12-15)% Mn + (2-5)% Ni Manganin is mainly used in electrical precision measuring instruments, shunt multipli...

  Question ; Miniature circuit breakers (MCB) are used in domestic and commercial installations for control and protection. What is the range of current rating of single pole MCB commercially available?  [SSC JE 2018] (a) 2 to 6 A (b) 0.5 to 60 A (c) 1 to 62 A (d) 6 to 32 A Answer : B This is standard range for current rating of MCB. It is used in home and industries. Hope your query is solved now. Comment below for any further queries. 

Question : The capacitor connected in parallel with an equipment provides some degree of protection against... (GETCO 2012)  A. Neutral displacement B. Ferranti effect  C. Loss of stability  D. Surges Answer : D Explanation :  Before the surge can impress a high voltage on the equipment, it must charge the capacitor.  By temporary energy storage in them, the modifiers reduce the steepness of the surge wave front, which otherwise can be damaging to apparatus, since the voltage across the equipment can rise only as quickly as the capacitor can be charged through the line.  Capacitors are particularly effective against short duration surges.  The energy of these surges is such that it can be absorbed by the capacitors.  However, for high energy surges, the size and cost of capacitors becomes prohibitive.  The combination of a capacitor and an arrester can be very useful because they complement each other. The capacitor reduces the steepness...

  Question : In Fast Decoupled Load Flow method, the matrices [H] and [L] are... (GETCO 2012)  A. Singular  B. Zero  C. Square  D. Unity Answer : C Explanation :   Dimensions of square matrix H = (n PQ + n PV )  Dimension of square matrix  L = n PQ Hope this explanation will help you to solve your queries. Please comment below for further queries. Thank you! 

  Question : In order to increase the limit of distance of transmission line... (GETCO 2012)   A. series resistances  B. shunt capacitors and series reactors  C. series capacitors and shunt reactors  D. synchronous condensers Answer : C Explanation :  Series capacitors compansates line inductance and shunt reactors absorb reactive power. Hence limit of distance of transmission line can be increased by series capacitors and shunt reactors.  Hope this explanation will help you to solve your queries. Please comment below for further queries. Thank you! 

  Question : The secondary distribution system (A.C.) employs... (GETCO 2012)  A. 3.0 kV, 3-phase, 3 wire system B. 6.6 kV, 3-phase, 3 wire system C. 1.0 kV, 3-phase, 3 wire system D. 400/230 V, 3-phase, 4 wire system  Answer : D Explanation : Secondary distribution is at voltage which is coming to residential houses. 4 wire system is required because each individual phase with neutral is used to give single phase supply. 4th wire is neutral wire. Hope this explanation will help you to solve your queries. Please comment below for further queries. Thank you! 

  Question :  Load flow study is carried out for... (GETCO 2012) A. fault calculations B. stability studies C. system planning D. load frequency control Answer : C Explanation : Load flow study is not useful in fault calculations, stability stydies and load frequency control. It is only useful for system planning.  Decide about which load to turn On and Off for particular time interval can be made by system planning.  Please comment below for further queries. Thank you! 

  Question : The transient stability limit of a power system can be appreciably increased by introducing A. series inductance B. shunt inductance C. series capacitance D. shunt capacitance Answer : C

 Question : Steady-state stability of a power system is improved by...  A. Reducing fault clearing time B. Using double circuit line instead of single circuit line C. Single pole switching D. Decreasing generator inertia Answer : B. Using double circuit line instead of single circuit line Because reactance of double circuit line is less than single line. So stability is more. 

Question : The load carrying capability of a long AC transmission line is    A. Always limited by the contactor size    B. Limited by stability considerations    C. Reduce at low ambient temperatures    D. Decreased by the use of bundled conductors of single conductors Answer : B

  Question : A.C. network analyser is used to solve problems of...    A. load flow  B. load flow and short-circuit  C. load flow and stability  D. load flow, short-circuit and stability Answer : D Because A. C. network analyser can measure voltage, current, power of each phase and by comparison of all three phase, detailed analysis can be performed.  Hope this explanation will help you to solve your queries. Please comment below for further queries. Thank you! 

  Question: For cost and safety the outdoor substations are installed for voltages above (a) 11 kV (b) 33 kV (c) 66 kV (d) 132 kV Answer: Option (b) 33 kV Because for voltage above 33 kV, it become uneconomical and complex to keep substation indoor.  If it is asked that  Beyond which voltage level outdoor type switchgear is installed in a power system network? Then answer is 66 kV.  For any further queries please comment below. Thank you! 

  Question: A 25 MVA, 4-pole, 50 Hz turbo-alternator has an inertia constant H = 5 kW sec/kVA. The stored kinetic energy in the rotor at synchronous speed is Explanation: Machine rating G = 25 MVA Inertia constant H = 5 kW sec/kVA Now kinetic energy stored (K. E.) = Machine rating * inertia constant K. E. = G*H K. E. = (25 MVA) * (5 kWsec/kVA) K. E. = 125 MJ

 Question:  A current of 5 A is flowing through magnesium wire. The current density is making an angle of 60° with Area vector. Find the electric field. (Given : Area 2 m² , ρ Resistivity of Magnesium 11× 10^-4 SI units) Solution :  E= J ρ  E =( I ρ) /A cos theta  E = (5 × 11 × 10^-4 )/ 2 cos 60°  E = 55 × 10^-4 V/m   

 Question : There is an electric field in x direction . If the work done in moving a charge 0.2 C through at a distance 2m along a line making an angle 60° with x axis is 4 J . The value of Electric field is ..... Solution :  given data , angle with x axis is 60°  Charge : 0.2 Coloumb  distance : 2 m  Work done : 4 J  Let see it in image for more detailed solution .  If you have any further queries then please comment below. 

 Question : An LVDT is connected to an amplifier of gain 250 the output terminals of which are connected to a 5 V voltmeter. The meter's scale can be read to 1/5th of a division and has 100 divisions in all. Given that a core displacement of 0.5 mm provides an output of 2 mV from the LVDT, find,  1. The sensitivity of the LVDT  2. The sensitivity of the whole system  3. The resolution of the instrument in centimeters Explanation : (a) Sensitivity of LVDT = Output voltage /displacement  Sensitivity of LVDT = 2mV/0.5 mm = 4 mV/mm (b)Sensitivity of whole setup = amplification factor*sensitivity of LVDT  Sensitivity of whole setup = 250*(4 mV/mm) = 1000 mV/mm (c) The resolution of the instrument in centimeters = minimum voltage that can be read by instrument /sensitivity of whole setup  There are 100 divisions to measure upto 5V.  So 1 division can read 5/100 = 0.05V Scale can read 1/5 of a division.  So minimum voltage that can be read = 0.05/5 ...

  Question : A college biology class consists of 8% freshmen, 27% sophomores, 45 % juniors and 20% seniors. During an exam, 22% of the freshmen, 17% of the sophomores, 12 % of the juniors, and 5% of the seniors wrote their answers in pen. If you would select an exam at random and find that the answers were written in pen, what is the probability that the exam was written by a freshmen? Explanation : Let us consider following events.  E1 = A college biology class consists of freshmen E2 = A college biology class consists of sophomores E3 = A college biology class consists of juniors E4 = A college biology class consists of seniors And P = student wrote their answers in pen  If answers were written in pen, probability that the exam was written by a freshmen P(E1 | P) = 0.1380

  Question: At which ampere amaron make battery 12V, 5AH should be charged? Answer: It is recommended that battery should be charged at about 25% of its amp-hour capacity.  25% of 5 AH = 25*5/100 = 1.25 Ampere So battery should not be changed at ampere more than 1.25 ampere. 

 QUESTION :- Find the LCM and HCF Of the following integers by applying the prime factorisation method.  1) 12,15 and 21  2) 17,23 and 29  3) 8,9 and 25 ANSWER :- 1) 12,15 and 21 Product of prime factor 12=2×2×3 = 2² × 3 15=3×5 21=3×7 Here, 3 is common among 12,15 and 21 SO, HCF(12,15,21) = 3 In LCM we have to multiply all number with highest power but number should not be repeated.  LCM(12,15,21)= 2² × 3¹ × 5¹ × 7¹ = 420 2) 17,23 and 29 17=1×17 23=1×23 29=1×29 Here, 1 is common among 17,23 and 29. So, HCF (17,23,29)=1 In LCM we have to multiply all number with highest power but number should not be repeated. LCM(17,23,29)=17×23×29=11,339 3) 8,9 and 25 8= 2×2×2×1 9=3×3×1 25=5×5×1 Here, 1 is common among 8,9 and 25. So,  HCF (8,9,25)=1 In LCM we have to multiply all number with highest power but number should not be repeated.  LCM(8,9,25)=2×2×2×3×3×5×5=1100

 Question : An Excel printout of some descriptive statistics for a set of data is shown below. What is the IQR?  Options:- A) 15.5 B) 38 C) 5.5 D) 15 Explanation :- IQR (Interquartile range) : IQR is a measure of where the middle fifty percent data is in a data set.  IQR is defined as first quartile(Q1) subtracted from third quartile(Q3).  IQR = Q3 - Q1 Here five number summary of data is given in question. We can calculate IQR from it.  From five number summary,  First quartile (Q1) = 5 Third quartile (Q3) = 20.5 IQR = Q3 - Q1 IQR = 20.5 - 5 IQR = 15.5  Comment below if you still have any queries. 

  Company:   HP Industry type:   Information technology and services Designation:   Area Sales Manager-Supplies Locations:   Lucknow, Uttar Pradesh, India. Job type:   Full-time Education Qualification required:  MBA with at least 2-5 years of professional experience in a related field. Diversity candidates will be preferred Skills required: ·         IT industry knowledge. ·         Strong communication skills. ·         Knowledge of promotional marketing processes and practices. Job responsibilities:                     Apply   basic foundation  of a function's principles, theories and concepts to assignments of limited scope. Uses professional concepts and theoretical knowledge acquired through specialized training, education or previous experi...

Company:   HP Industry type:   Information technology and services Designation:   Program Manager Field delivery operations Locations:   Chennai, Tamil Nadu, India. Job type:   Full-time Education Qualification required:  ·         First Level University degree. ·         7+ years in project management roles or in like roles/businesses. Skills required: ·         Demonstrates an in-depth understanding of key Services' operational policies, processes and methodologies applicable to project management. ·         Data analytics skills ·         Speaks with authority to most layers of depth related to project management methods. ·         Makes use of and contributes to Services PM Profession community. ·     ...

Company:   HP Industry type:   Information technology and services Designation:   Customer Care Center Global End-To-End Process Engineer Locations:   Bangalore, Karnataka, India. Job type:   Full-time Education Qualification required:  ·         Bachelor's degree in Computer Science, Process Engineering, Business Administration or equivalent diploma or experience ·         8+ years of experience in Customer Support ·         Experience in Process Management ·         Experience in virtual team environment ·         Experience in Call Center support environment. Good understanding of Call Center Processes, Tools and Agent Experience will be considered a plus ·         Experience in working with Global Teams is a definite plus ·...